- Home
- Standard 11
- Physics
14.Waves and Sound
normal
When a wave travels in a medium, the particle displacement is given by : $y = asin\, 2 \pi \,(bt -cx)$, where $a, b$ and $c$ are constants. The maximum particle velocity will be twice the wave velocity if
A
$c = \frac{1}{\pi a}$
B
$c = \pi a$
C
$b = ac$
D
$b = \frac{1}{ac}$
Solution
For the wave $A \sin (\omega t-k x),$ wave velocity is $\frac{\omega}{k}$ and maximum particle velocity is $\omega A$
Therefore:
For the given wave, the wave speed is given by, $v_{w}=\frac{b}{c}$
And the maximum particle speed is given by: $v_{p}=2 \pi a b$ So, $v_{p}=2 v_{w}$
$\Rightarrow c=\frac{1}{\pi a}$
Standard 11
Physics
Similar Questions
normal
normal