When an α - particle of mass m moving with velocity v bombards on a heavy nucleus of charge Zₑ ,

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12.Atoms

medium

When an $\alpha -$particle of mass $m$ moving with velocity $v$ bombards on a heavy nucleus of charge $Z_e$ , its distance of closest approach from the nucleus depends on $m$ as

$\frac{1}{{{m^2}}}$

$m$

$\frac{1}{m}$

$\frac{1}{{\sqrt m }}$

(NEET-2016)

Solution

Distance of closest approach when an $\alpha$ particle of mass $m$ moving with velocity $v$ is bombarded on a heavy nucleus of charge $Z e,$ is given by

$r_{0}=\frac{Z e^{2}}{\pi \varepsilon_{0} m v^{2}} $ $\therefore r_{0} \propto \frac{1}{m}$

Standard 12

Physics

In an alpha particle scattering experiment distance of closest approach for the $\alpha$ particle is $4.5 \times 10^{-14} \mathrm{~m}$. If target nucleus has atomic number $80$ , then maximum velocity of $\alpha$-particle is . . . . .. $\times 10^5$ $\mathrm{m} / \mathrm{s}$ approximately.

$\left(\frac{1}{4 \pi \epsilon_0}=9 \times 10^9 \mathrm{SI}\right.$ unit, mass of $\alpha$ particle $=$ $\left.6.72 \times 10^{-27} \mathrm{~kg}\right)$

hard

(JEE MAIN-2024)

In a Rutherford scattering experiment when a projectile of charge $z_1$ and mass $M_1$ approaches a target nucleus of charge $z_2$ and mass $M_2$, the distance of closest approach is $r_0$ The energy of the projectile is

medium

(AIPMT-2009)

If radiation of allow wavelengths from ultraviolet to infrared is passed through hydrogen agas at room temperature, absorption lines will be observed in the :

normal

According to classical theory, the circular path of an electron in Rutherford atom is

easy

A beam of fast moving alpha particles were directed towards a thin film of gold. The parts $A',\;B'$ and $C'$of the transmitted and reflected beams corresponding to the incident parts $A, B$ and $C$ of the beam, are shown in the adjoining diagram. The number of alpha particles in