When vector overrightarrow{ A }=2 hat{ i }+3 hat{ j }+2 hat{ k } is subtracted from vector vec{B} ,

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3-1.Vectors

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When vector $\overrightarrow{ A }=2 \hat{ i }+3 \hat{ j }+2 \hat{ k }$ is subtracted from vector $\vec{B}$, it gives a vector equal to $2 \hat{j}$. Then the magnitude of vector $\vec{B}$ will be:

A

$\sqrt{13}$

B

$\sqrt{33}$

C

$\sqrt{6}$

D

$\sqrt{5}$

(JEE MAIN-2023)

Solution

$\overrightarrow{ B }-\overrightarrow{ A }=2 j$

$\overrightarrow{ B }=2 \hat{ i }+5 \hat{ j }+2 \hat{ k }$

$|\overrightarrow{ B }|=\sqrt{33}$

Standard 11

Physics

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