M{L^3}{T^{ - 1}}{Q^{ - 2}} is dimension of | vedclass

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Question

(a) Resistivity $[ho ] = \frac{{[R]\,.\,[A]}}{{[l]}}$
${m{where }} [R] = [M{L^2}{T^{ - 1}}{Q^{ - 2}}]$
$	herefore $ $[ho ] = [M{L^3}{T^{ - 1}

Vedclass · Accepted Answer

Resistivity

Vedclass · Answer

(a) Resistivity $[ho ] = \frac{{[R]\,.\,[A]}}{{[l]}}$
${m{where }} [R] = [M{L^2}{T^{ - 1}}{Q^{ - 2}}]$
$	herefore $ $[ho ] = [M{L^3}{T^{ - 1}}{Q^{ - 2}}]$

$M{L^3}{T^{ - 1}}{Q^{ - 2}}$ is dimension of

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