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1.Units, Dimensions and Measurement
medium
$M{L^3}{T^{ - 1}}{Q^{ - 2}}$ is dimension of
AResistivity
BConductivity
CResistance
DNone of these
Solution
(a) Resistivity $[\rho ] = \frac{{[R]\,.\,[A]}}{{[l]}}$
${\rm{where }} [R] = [M{L^2}{T^{ – 1}}{Q^{ – 2}}]$
$\therefore $ $[\rho ] = [M{L^3}{T^{ – 1}}{Q^{ – 2}}]$
${\rm{where }} [R] = [M{L^2}{T^{ – 1}}{Q^{ – 2}}]$
$\therefore $ $[\rho ] = [M{L^3}{T^{ – 1}}{Q^{ – 2}}]$
Standard 11
Physics
Similar Questions
Match List$-I$ with List$-II.$
| List$-I$ | List$-II$ |
| $(a)$ Capacitance, $C$ | $(i)$ ${M}^{1} {L}^{1} {T}^{-3} {A}^{-1}$ |
| $(b)$ Permittivity of free space, $\varepsilon_{0}$ | $(ii)$ ${M}^{-1} {L}^{-3} {T}^{4} {A}^{2}$ |
| $(c)$ Permeability of free space, $\mu_{0}$ | $(iii)$ ${M}^{-1} L^{-2} T^{4} A^{2}$ |
| $(d)$ Electric field, $E$ | $(iv)$ ${M}^{1} {L}^{1} {T}^{-2} {A}^{-2}$ |
