Which one of the following molecules is expec | vedclass

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Question

$\pi 2 p_{x}^{2} \approx \pi 2 p_{y}^{2}$

Since, all the' electrons are paired, it is a diamagnetic specie. $\mathrm{N}_{2}(7+7=14)=\sigma 1 \m

Vedclass · Accepted Answer

$C_2$

Vedclass · Answer

$\pi 2 p_{x}^{2} \approx \pi 2 p_{y}^{2}$

Since, all the' electrons are paired, it is a diamagnetic specie. $\mathrm{N}_{2}(7+7=14)=\sigma 1 \mathrm{s}^{2},{ }^{\star} \mathrm{\sigma} \cdot 1 \mathrm{s}^{2}, \sigma 2 \mathrm{s}^{2}$

$\stackrel{*}{\sigma} 2 s^{2}, \pi 2 p_{x}^{2} \approx \pi 2 p_{y}^{2}, \sigma 2 p_{z}^{2}$

It is also a diamagnetic specie because of the absence of unpaired electrons.

$0_{2}(8+8=16)$

$\mathrm{Or} \quad \mathrm{S}_{2}=\sigma 1 \mathrm{s}^{2}, \stackrel{*}{\sigma} 1 \mathrm{s}^{2}, \sigma 2 \mathrm{s}^{2},{ }^{*} 2 \mathrm{s}^{2}$

$\sigma 2 p_{z}^{2}, \pi 2 p_{x}^{2} \approx \pi 2 p_{y}^{2}, \pi 2 p_{x}^{1} \approx \pi 2 p_{y}^{1}$

Since, $\mathrm{O}_{2}$ or $\mathrm{S}_{2}$ contain 2 unpaired electrons, therefore they are paramagnetic.

List$-I$	List$-II$
$(a)$ $Ne _{2}$	$(i)$ $1$
$(b)$ $N _{2}$	$(ii)$ $2$
$(c)$ $F _{2}$	$(iii)$ $0$
$(d)$ $O _{2}$	$(iv)$ $3$

Which one of the following molecules is expected to exhibit diamagnetic behaviour ?

Similar Questions

Match List$-I$ with List$-II.$

List$-I$ List$-II$

$(a)$ $Ne _{2}$ $(i)$ $1$

$(b)$ $N _{2}$ $(ii)$ $2$

$(c)$ $F _{2}$ $(iii)$ $0$

$(d)$ $O _{2}$ $(iv)$ $3$

Choose the correct answer from the options given below:

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