$\pi 2 p_{x}^{2} \approx \pi 2 p_{y}^{2}$

Since, all the' electrons are paired, it is a diamagnetic specie. $\mathrm{N}_{2}(7+7=14)=\sigma 1 \mathrm{s}^{2},{ }^{\star} \mathrm{\sigma} \cdot 1 \mathrm{s}^{2}, \sigma 2 \mathrm{s}^{2}$

$\stackrel{*}{\sigma} 2 s^{2}, \pi 2 p_{x}^{2} \approx \pi 2 p_{y}^{2}, \sigma 2 p_{z}^{2}$

It is also a diamagnetic specie because of the absence of unpaired electrons.

$0_{2}(8+8=16)$

$\mathrm{Or} \quad \mathrm{S}_{2}=\sigma 1 \mathrm{s}^{2}, \stackrel{*}{\sigma} 1 \mathrm{s}^{2}, \sigma 2 \mathrm{s}^{2},{ }^{*} 2 \mathrm{s}^{2}$

$\sigma 2 p_{z}^{2}, \pi 2 p_{x}^{2} \approx \pi 2 p_{y}^{2}, \pi 2 p_{x}^{1} \approx \pi 2 p_{y}^{1}$

Since, $\mathrm{O}_{2}$ or $\mathrm{S}_{2}$ contain 2 unpaired electrons, therefore they are paramagnetic.