Why can’t molecularity of any reaction be equal to zero ?
Why can’t molecularity of any reaction be equal to zero ?
Molecularity is the number of molecules taking part in an elementary step. For this we require at least a single molecule leading to the value of minimum molecularity of one.
Similar Questions
During Kinetic study of reaction $2 A+B \rightarrow C+D$, the following results were obtained :
$A[M]$
$B[M]$
initial rate of
formation of $D$
$i$
$0.1$
$0.1$
$6.0 \times 10^{-3}$
$ii$
$0.3$
$0.2$
$7.2 \times 10^{-2}$
$ii$
$0.3$
$0.4$
$2.88 \times 10^{-1}$
$iv$
$0.4$
$0.1$
$2.40 \times 10^{-2}$
Based on above data, overall order of the reaction is $\qquad$
During Kinetic study of reaction $2 A+B \rightarrow C+D$, the following results were obtained :
| $A[M]$ | $B[M]$ |
initial rate of formation of $D$ |
|
| $i$ | $0.1$ | $0.1$ | $6.0 \times 10^{-3}$ |
| $ii$ | $0.3$ | $0.2$ | $7.2 \times 10^{-2}$ |
| $ii$ | $0.3$ | $0.4$ | $2.88 \times 10^{-1}$ |
| $iv$ | $0.4$ | $0.1$ | $2.40 \times 10^{-2}$ |
Based on above data, overall order of the reaction is $\qquad$
- [JEE MAIN 2024]
The rate constant for the reaction, $2N_2O_5 \to 4NO_2 + O_2$ is $3.0\times 10^{- 4}\,s^{-1}$ . If start made with $1.0\,mol\,L^{-1}$ of $N_2O_5$, calculate the rate of formation of $NO_2$ at the moment of the reaction when concentration of $O_2$ is $0.1\, mol\, L^{-1}$.
The rate constant for the reaction, $2N_2O_5 \to 4NO_2 + O_2$ is $3.0\times 10^{- 4}\,s^{-1}$ . If start made with $1.0\,mol\,L^{-1}$ of $N_2O_5$, calculate the rate of formation of $NO_2$ at the moment of the reaction when concentration of $O_2$ is $0.1\, mol\, L^{-1}$.
- [AIIMS 2011]
Which one of the following statement for order of reaction is not correct ?
Which one of the following statement for order of reaction is not correct ?
Write unit of rate constant of following reaction :
$1.$ fourth order
$2.$ third order
Write unit of rate constant of following reaction :
$1.$ fourth order
$2.$ third order
For the reaction
$2 \mathrm{H}_{2}(\mathrm{g})+2 \mathrm{NO}(\mathrm{g}) \rightarrow \mathrm{N}_{2}(\mathrm{g})+2 \mathrm{H}_{2} \mathrm{O}(\mathrm{g})$
the observed rate expression is, rate $=\mathrm{k}_{\mathrm{f}}[\mathrm{NO}]^{2}\left[\mathrm{H}_{2}\right] .$ The rate expression of the reverse reaction is
For the reaction
$2 \mathrm{H}_{2}(\mathrm{g})+2 \mathrm{NO}(\mathrm{g}) \rightarrow \mathrm{N}_{2}(\mathrm{g})+2 \mathrm{H}_{2} \mathrm{O}(\mathrm{g})$
the observed rate expression is, rate $=\mathrm{k}_{\mathrm{f}}[\mathrm{NO}]^{2}\left[\mathrm{H}_{2}\right] .$ The rate expression of the reverse reaction is
- [JEE MAIN 2020]