Why do we apply paint on iron articles ?

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1. Chemical Reactions and Equations

easy

Why do we apply paint on iron articles ?

Option A

Option B

Option C

Option D

Solution

Iron articles are painted because it prevents them from rusting. When painted, the contact of iron articles from moisture and air is cut off. Hence, rusting is prevented their presence is essential for rusting to take place.

Standard 10

Science

What does one mean by exothermic and endothermic reactions ? Give examples.

medium

In the refining of silver, the recovery of silver from silver nitrate solution involved displacement by copper metal. Write down the reaction involved.

medium

Why are decomposition reactions called the opposite of combination reactions? Write equations for these reactions.

medium

Which of the statements about the reaction below are incorrect ?

$2 PbO _{( s )}+ C _{( s )} \longrightarrow 2 Pb _{( s )}+ CO _{2( g )}$

$(a)$ Lead is getting reduced.

$(b)$ Carbon dioxide is getting oxidised.

$(c)$ Carbon is getting oxidised.

$(d)$ Lead oxide is getting reduced.

easy

What is a balanced chemical equation ? Why should chemical equations be balanced ?

medium

Why do we apply paint on iron articles ?

Solution

Similar Questions

What does one mean by exothermic and endothermic reactions ? Give examples.

In the refining of silver, the recovery of silver from silver nitrate solution involved displacement by copper metal. Write down the reaction involved.

Why are decomposition reactions called the opposite of combination reactions? Write equations for these reactions.

Which of the statements about the reaction below are incorrect ? $2 PbO _{( s )}+ C _{( s )} \longrightarrow 2 Pb _{( s )}+ CO _{2( g )}$ $(a)$ Lead is getting reduced. $(b)$ Carbon dioxide is getting oxidised. $(c)$ Carbon is getting oxidised. $(d)$ Lead oxide is getting reduced.

What is a balanced chemical equation ? Why should chemical equations be balanced ?

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Which of the statements about the reaction below are incorrect ?

$2 PbO _{( s )}+ C _{( s )} \longrightarrow 2 Pb _{( s )}+ CO _{2( g )}$

$(a)$ Lead is getting reduced.

$(b)$ Carbon dioxide is getting oxidised.

$(c)$ Carbon is getting oxidised.

$(d)$ Lead oxide is getting reduced.