Why does the colour of copper sulphate solution change when an iron nail is dipped in it ?
When an iron nail is placed in a copper sulphate solution, iron displaces copper from copper sulphate solution forming iron sulphate, which is green in colour.
$\underset{Iron}{\mathop{F{{e}_{(s)}}}}\,+\underset{\begin{smallmatrix}
Copper\text{ }sulphate \\
\left( Blue\text{ }colour \right)~
\end{smallmatrix}}{\mathop{CuS{{O}_{4\left( aq \right)}}}}\,\to \underset{\begin{smallmatrix}
Iron\text{ }sulphate \\
\left( Green\text{ }colour \right)
\end{smallmatrix}}{\mathop{FeS{{O}_{4\left( aq \right)}}}}\,+\underset{Copper}{\mathop{C{{u}_{(s)}}}}\,$
Therefore, the blue colour of copper sulphate solution fades and green colour appears.
Why are decomposition reactions called the opposite of combination reactions? Write equations for these reactions.
Balance the following chemical equations.
$(a)$ $HNO _{3}+ Ca ( OH )_{2} \longrightarrow Ca \left( NO _{3}\right)_{2}+ H _{2} O$
$(b)$ $NaOH + H _{2} SO _{4} \longrightarrow Na _{2} SO _{4}+ H _{2} O$
$(c)$ $NaCl + AgNO _{3} \longrightarrow AgCl + NaNO _{3}$
$(d)$ $BaCl _{2}+ H _{2} SO _{4} \longrightarrow BaSO _{4}+ HCl$
Explain the ''Corrosion'' terms with one example.
$Fe _{2} O _{3}+2 Al \rightarrow Al _{2} O _{3}+2 Fe$
The above reaction is an example of a
Explain the "Reduction'' in terms of gain or loss of oxygen with two examples.