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2. Polynomials
hard
ઘનનું મૂલ્ય મેળવ્યા સિવાય નીચેનાની કિંમત મેળવો.
$(0.2)^{3}-(0.3)^{3}+(0.1)^{3}$
A
$0.018$
B
$-1$
C
$1$
D
$-0.018$
Solution
We have,
$(0.2)^{3}-(0.3)^{3}+(0.1)^{3}=(0.2)^{3}+(-0.3)^{3}+(0.1)^{3}$
Let $a=0.2, b=-0.3$ and $c=0.1 .$ Then,
$a+b+c=0.2+(-0.3)+0.1$
$=0.2-0.3+0.1=0$
$a+b+c=0$
$a^{3}+b^{3}+c^{3}=0=3 a b c$
$(0.2)^{3}+(-0.3)^{3}+(0.1)^{3}=3(0.2)(-0.3)(0.1)=-0.018$
Hence,$(0.2)^{3}+(-0.3)^{3}+(0.1)^{3}=-0.018$
Standard 9
Mathematics
