2. Polynomials
medium

$(3 a+4 b+5 c)^{2}$ को प्रसारित रूप में लिखिए।

Option A
Option B
Option C
Option D

Solution

Comparing the given expression with $(x+y+z)^{2}$, we find that

$x=3 a,\, y=4 b$ and $z=5 c$.

Therefore, using Identity $V$, we have

$(3 a+4 b+5 c)^{2} =(3 a)^{2}+(4 b)^{2}+(5 c)^{2}+2(3 a)(4 b)+2(4 b)(5 c)+2(5 c)(3 a)$

$=9 a^{2}+16 b^{2}+25 c^{2}+24 a b+40 b c+30 a c$

Standard 9
Mathematics

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