8. Introduction to Trigonometry
easy

Write 'True' or 'False' and justify your answer.

$\frac{\tan 47^{\circ}}{\cot 43^{\circ}}=1$

Option A
Option B
Option C
Option D

Solution

True

$\frac{\tan 47^{\circ}}{\cot 43^{\circ}}=\frac{\tan \left(90^{\circ}-43^{\circ}\right)}{\cot 43^{\circ}}=\frac{\cot 43^{\circ}}{\cot 43^{\circ}}=1 \quad\left[\because \tan \left(90^{\circ}-\theta\right)=\cot \theta\right]$

Standard 10
Mathematics

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