‘At surface of a charged conductor electrostatic field must be normal to surface at every poin

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2. Electric Potential and Capacitance

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‘At the surface of a charged conductor electrostatic field must be normal to the surface at every point’. Explain.

Option A

Option B

Option C

Option D

Solution

If $\overrightarrow{\mathrm{E}}$ were not normal to the surface, it would have some non-zero component along the surface. Free charges on the surface of the conductor would then experience force and move. Hence, conductor does not remains in stable situation.

Therefore, $\vec{E}$ should have no tangential component parallel to the surface in stable situation. Thus, electrostatic field at the surface of a charged conductor must be normal to the surface at every point. (For a conductor without any surface charge density, field is zero even at the surface).

$\left[\because 0=\frac{\sigma}{\epsilon_{0}}\right]$

Standard 12

Physics

Two charged conducting spheres of radii $a$ and $b$ are connected to each other by a wire. What is the ratio of electric fields at the surfaces of the two spheres? Use the result obtained to explain why charge density on the sharp and pointed ends of a conductor is higher than on its flatter portions.

medium

A solid spherical conducting shell has inner radius a and outer radius $2a$. At the center of the shell is located a point charge $+Q$. What must the excess charge of the shell be in order for the charge density on the inner and outer surfaces of the shell to be exactly equal ?

medium

A conducting sphere of radius $10\, cm$ is charged $10\,\mu \,C$. Another uncharged sphere of radius $20\, cm$ is allowed to touch it for some time. After that if the sphere are separated, then surface density of charges, on the spheres will be in the ratio of

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(AIIMS-2002)

Four metal conductors having different shapes

$1.$ A sphere $2.$ Cylindrical

$3.$ Pear $4.$ Lightning conductor

are mounted on insulating stands and charged. The one which is best suited to retain the charges for a longer time is

easy

Aspherical shell with an inner radius $'a'$ and an outer radius $'b' $ is made of conducting material. A point charge $+Q$ is placed at the centre of the spherical shell and a total charge $- q $ is placed on the shell.

Charge $- q $ is distributed on the surfaces as

hard

‘At the surface of a charged conductor electrostatic field must be normal to the surface at every point’. Explain.

Solution

Similar Questions

A solid spherical conducting shell has inner radius a and outer radius $2a$. At the center of the shell is located a point charge $+Q$. What must the excess charge of the shell be in order for the charge density on the inner and outer surfaces of the shell to be exactly equal ?

A conducting sphere of radius $10\, cm$ is charged $10\,\mu \,C$. Another uncharged sphere of radius $20\, cm$ is allowed to touch it for some time. After that if the sphere are separated, then surface density of charges, on the spheres will be in the ratio of

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Four metal conductors having different shapes

$1.$ A sphere $2.$ Cylindrical

$3.$ Pear $4.$ Lightning conductor

are mounted on insulating stands and charged. The one which is best suited to retain the charges for a longer time is

Aspherical shell with an inner radius $'a'$ and an outer radius $'b' $ is made of conducting material. A point charge $+Q$ is placed at the centre of the spherical shell and a total charge $- q $ is placed on the shell.

Charge $- q $ is distributed on the surfaces as