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6-2.Equilibrium-II (Ionic Equilibrium)
medium
$0.1$ $mol$ of $H_2S(g)$ is kept in a $0.4$ litre vessel at $1000\,K$. For the reaction -
$2{H_2}S(g)\,\rightleftharpoons\,2{H_2}(g)\, + \,{S_2}(g)\,;\,{K_c} = {10^{ - 6}}\% $ dissociation of $H_2S$ is.......$\%$
A
$0.5$
B
$1$
C
$2$
D
$3$
Solution
$\mathop {2{H_2}S(g)}\limits_{0.25\,[1 – \alpha ]} \leftrightarrow \mathop {2{H_2}}\limits_{0.25\alpha } + \mathop {{S_2}}\limits_{\frac{{0.25\alpha }}{2}} $
Approx : $\alpha<<1$
$10^{-6}=\frac{(0.25 \alpha)^{2}-\left(\frac{0.25 \alpha}{2}\right)}{(0.25)^{2}}=\alpha^{3}(0.125)$
$\alpha=2 \times 10^{-2}$
Standard 11
Chemistry
