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3-1.Vectors
easy
A vector is represented by $3\,\hat i + \hat j + 2\,\hat k$. Its length in $XY$ plane is
A$2$
B$\sqrt {14} $
C$\sqrt {10} $
D$\sqrt 5 $
Solution
(c) $\vec R = 3\hat i + \hat j + 2\hat k$
Length in $XY$ plane = $\sqrt {R_x^2 + R_y^2} = \sqrt {{3^2} + {1^2}} $$ = \sqrt {10} $
Length in $XY$ plane = $\sqrt {R_x^2 + R_y^2} = \sqrt {{3^2} + {1^2}} $$ = \sqrt {10} $
Standard 11
Physics
