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10-1.Thermometry, Thermal Expansion and Calorimetry
normal
$50\,g$ of copper is heated to increase is temperature by $10\,^oC$. If the same quantity of heat is given to $10\,g$ of water, the rise in its temperature is ........ $^oC$ (Specific heat of copper $= 420\,J-kg^{-1}\,^oC^{-1}$ )
A
$5$
B
$6$
C
$7$
D
$8$
Solution
$\Delta \theta_{\mathrm{w}}=\frac{\mathrm{m}_{\mathrm{C}} \mathrm{c}_{\mathrm{C}}(\Delta \theta)_{\mathrm{C}}}{\mathrm{m}_{\mathrm{W}} \mathrm{C}_{\mathrm{W}}}$
$=\frac{50 \times 10^{-3} \times 420 \times 10}{10 \times 10^{-3} \times 4200}$
$=5^{\circ} \mathrm{C}$
Standard 11
Physics