The $ pH$ of $ 0.1$ $M$ acetic acid is $3$, the dissociation constant of acid will be
The $ pH$ of $ 0.1$ $M$ acetic acid is $3$, the dissociation constant of acid will be
- A
$1.0 \times {10^{ - 4}}$
- B
$1.0 \times {10^{ - 5}}$
- C
$1.0 \times {10^{ - 3}}$
- D
$1.0 \times {10^{ - 8}}$
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