$(a)$ The peak voltage of an $ac$ supply is $300\; V$. What is the $rms$ voltage?
$(b)$ The $rms$ value of current in an ac circuit is $10\; A$. What is the peak current?
$(a)$ Peak voltage of the ac supply, $V _{0}=300 \,V$ We know
$V_{m x}=\frac{V_{0}}{\sqrt{2}}=\frac{300}{\sqrt{2}}=212.1\, V$
$(b)$ The $rms$ value of current is given as $ I=10\,A$ Using above identity for current peak current is given as:
$I _{0}=1.414 \times I _{ rms }$
$I _{0}=1.414 \times 10=14.14 \,A$
In an $ac$ circuit $I = 100\, sin \,200$ $\pi t.$ The time required for the current to achieve its peak value will be
When a $DC$ voltage of $200\, V$ is applied to a coil of self inductance $\frac{{2\sqrt 3 }}{\pi }\,H$, a current of $1\, A$ flows through it. But by replacing $DC$ source with $AC$ source of $200\, V$, the current in the coil is reduced to $0.5\, A$. Then, the frequency of $AC$ supply is......$Hz$
A direct current of $5\,A$ is superposed on an alternating current $I =10 \sin \omega t$ flowing through the wire. The effective value of the resulting current will be
The peak voltage of the ac source is equal to:
A complex current wave is given by $i = 5 + 5\, sin\, (100\, \omega t)\, A$. Its average value over one time period is given as.....$A$