A and B are two events such that P(A)=0.54 , P(B)=0.69 and P(A cap B)=0.35. Find P ( A cup B )

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14.Probability

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$A$ and $B$ are two events such that $P(A)=0.54$, $P(B)=0.69$ and $P(A \cap B)=0.35.$ Find $P ( A \cup B )$.

A

$0.88$

B

$0.88$

C

$0.88$

D

$0.88$

Solution

It is given that $P ( A )=0.54$, $P ( B )=0.69$, $P (A \cap B)=0.35$

We know that $P (A \cup B)= P ( A )+ P ( B )- P (A \cap B)$

$\therefore P (A \cup B)=0.54+0.69-0.35=0.88$

Standard 11

Mathematics

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