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14.Probability
easy
$A$ and $B$ are two events such that $P(A)=0.54$, $P(B)=0.69$ and $P(A \cap B)=0.35.$ Find $P ( A \cup B )$.
A
$0.88$
B
$0.88$
C
$0.88$
D
$0.88$
Solution
It is given that $P ( A )=0.54$, $P ( B )=0.69$, $P (A \cap B)=0.35$
We know that $P (A \cup B)= P ( A )+ P ( B )- P (A \cap B)$
$\therefore P (A \cup B)=0.54+0.69-0.35=0.88$
Standard 11
Mathematics