There are four men and six women on the city council. If one council member is selected for a committee at random, how likely is it that it is a woman?
There are four men and six women on the city council. If one council member is selected for a committee at random, how likely is it that it is a woman?
There are four men and six women on the city council.
As one council member is to be selected for a committee at random, the sample space contains $10(4+6)$ elements.
Let A be the event in which the selected council member is a woman.
Accordingly, $n ( A )=6$
$\therefore P ( A )=\frac{\text { Number of outcomes favourable to } A }{\text { Total number of possible outcomes }}=\frac{n( A )}{n( S )}=\frac{6}{10}=\frac{3}{5}$
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