0.01 moles of a weak acid HA left( K _{ a }=2 | vedclass

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Question

$\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\quad\quad\quad HA \rightleftharpoons \quad H ^{+}+\quad A ^{-}$

Initial conc. $\quad0.01 M\quad \, 0.1 M \qua

Vedclass · Accepted Answer

$2$

Vedclass · Answer

$\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\quad\quad\quad HA ightleftharpoons \quad H ^{+}+\quad A ^{-}$

Initial conc. $\quad0.01 M\quad \, 0.1 M \quad\quad 0$

Equ. conc. $\,(0.01- x )\quad(0.1+ x )\quad xM$

Now, $K_{a}=\frac{\left[x^{+}ight]\left[A^{-}ight]}{[H A]} \Rightarrow 2 	imes 10^{-6}=\frac{0.1 	imes x}{0.01}$

$	herefore \quad x=2 	imes 10^{-7}$

Now, $\alpha=\frac{x}{0.01}=\frac{2 	imes 10^{-7}}{0.01}=2 	imes 10^{-5}$

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