Mathematical Reasoning
hard

$( S 1)( p \Rightarrow q ) \vee( p \wedge(\sim q ))$ is a tautology $( S 2)((\sim p ) \Rightarrow(\sim q )) \wedge((\sim p ) \vee q )$ is a Contradiction. Then

A

only $(S2)$ is correct

B

both $(S1)$ and $(S2)$ are correct

C

both $(S1)$ and $(S2)$ are wrong

D

only $(S1)$ is correct

(JEE MAIN-2023)

Solution

Standard 11
Mathematics

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