- Home
- Standard 11
- Mathematics
Mathematical Reasoning
hard
$( S 1)( p \Rightarrow q ) \vee( p \wedge(\sim q ))$ is a tautology $( S 2)((\sim p ) \Rightarrow(\sim q )) \wedge((\sim p ) \vee q )$ is a Contradiction. Then
A
only $(S2)$ is correct
B
both $(S1)$ and $(S2)$ are correct
C
both $(S1)$ and $(S2)$ are wrong
D
only $(S1)$ is correct
(JEE MAIN-2023)
Solution

Standard 11
Mathematics