Consider the following two propositions:

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Question

$p$
			$q$
			$\sim p$
			$\sim q$
			$\sim p \vee q$
			$p \rightarrow(\sim p  \vee q )$
			$( p \rightarrow \sim q )$
			$\s

Vedclass · Accepted Answer

Both $P_1$ and $P_2$ are FALSE

Vedclass · Answer

$p$
			$q$
			$\sim p$
			$\sim q$
			$\sim p \vee q$
			$p \rightarrow(\sim p  \vee q )$
			$( p \rightarrow \sim q )$
			$\sim( p \rightarrow \sim q )$
			$p \wedge \sim q$
			$p_2$
		
		
			$T$
			$T$
			$F$
			$F$
			$T$
			$T$
			$F$
			$T$
			$F$
			$F$
		
		
			$T$
			$F$
			$F$
			$T$
			$F$
			$F$
			$T$
			$F$
			$T$
			$F$
		
		
			$F$
			$T$
			$T$
			
			$F$
			
			$T$
			$T$
			$T$
			$F$
			$F$
			$F$
		
		
			$F$
			$F$
			$T$
			$T$
			$T$
			$T$
			$T$
			$F$
			$F$
			$F$
		
	


$p \rightarrow(\sim p \vee q )$ is $F$ when $p$ is true $q$ is false

From table

$P_1$ and $P_2$ both are false

Consider the following two propositions:

$P_1: \sim( p \rightarrow \sim q )$

$P_2:( p \wedge \sim q ) \wedge((\sim p ) \vee q )$

If the proposition $p \rightarrow((\sim p ) \vee q )$ is evaluated as $FALSE$, then

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