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6-2.Equilibrium-II (Ionic Equilibrium)
medium
$0.01\,M$ acetic acid solution is $1 \%$ ionised, then $pH$ of this acetic acid solution is :
A$3$
B$2$
C$4$
D$1$
(NEET-2022)
Solution
For $CH _3 COOH$ :
${\left[ H ^{+}\right]= C \cdot \alpha}$
${\left[ H ^{+}\right]=10^{-2} \times \frac{1}{100}=10^{-4}\,M }$
$pH =-\log \left[ H ^{+}\right]$
$pH =-\log 10^{-4}$
$pH =4$
${\left[ H ^{+}\right]= C \cdot \alpha}$
${\left[ H ^{+}\right]=10^{-2} \times \frac{1}{100}=10^{-4}\,M }$
$pH =-\log \left[ H ^{+}\right]$
$pH =-\log 10^{-4}$
$pH =4$
Standard 11
Chemistry
