PH of 0.1 ,M solution of a weak monoprotic acid 1% ionized is

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6-2.Equilibrium-II (Ionic Equilibrium)

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The $pH$ of $ 0.1 \,M$ solution of a weak monoprotic acid $1\%$ ionized is

A

$1$

B

$2$

C

$3$

D

$4$

Solution

(c) $C = 0.1\,M;\,\,\,\,\alpha = 1\% ;\,\,\,\,({H^ + }) = C \times \alpha $

$ = 0.1 \times \frac{1}{{100}} = {10^{ – 3}}$; $({H^ + }) = {10^{ – 3}}$; $pH = 3$.

Standard 11

Chemistry

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