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Basic of Logarithms
easy
${{{{2.3}^{n + 1}} + {{7.3}^{n - 1}}} \over {{3^{n + 2}} - 2{{(1/3)}^{l - n}}}} = $
A
$1$
B
$3$
C
$-1$
D
$0$
Solution
(a) ${{{{2.3}^{n + 1}} + {{7.3}^{n – 1}}} \over {{3^{n + 2}} – 2{{\left( {{1 \over 3}} \right)}^{1 – n}}}} = {{{{2.3}^{n – 1}}{{.3}^2} + {{7.3}^{n – 1}}} \over {{3^{n – 1}}{{.3}^3} – {{2.3}^{n – 1}}}} = {{{3^{n – 1}}[18 + 7]} \over {{3^{n – 1}}[27 – 2]}} = 1$.
Standard 11
Mathematics
