Solution of the equation sqrt {(x + 10)} + sq | vedclass

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Question

(b) $\sqrt {x + 10} + \sqrt {x - 2} = 6$$ \Rightarrow $$\sqrt {x + 10} = 6 - \sqrt {x - 2} $

$ \Rightarrow $ $x + 10 = 36 + x - 2 - 12\sqrt {x - 2}

Vedclass · Accepted Answer

$6$

Vedclass · Answer

(b) $\sqrt {x + 10} + \sqrt {x - 2} = 6$$ \Rightarrow $$\sqrt {x + 10} = 6 - \sqrt {x - 2} $

$ \Rightarrow $ $x + 10 = 36 + x - 2 - 12\sqrt {x - 2} $

$ \Rightarrow $ $2 = \sqrt {x - 2} $ $ \Rightarrow $ $4 = x - 2$ $ \Rightarrow $ $x = - 6$

This value satisfies the given equation.

$	herefore x=6$.

Solution of the equation $\sqrt {(x + 10)} + \sqrt {(x - 2)} = 6$ are

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