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6.Permutation and Combination
easy
$^n{C_r} + {2^n}{C_{r - 1}}{ + ^n}{C_{r - 2}} = $
A
$^{n + 1}{C_r}$
B
$^{n + 1}{C_{r + 1}}$
C
$^{n + 2}{C_r}$
D
$^{n + 2}{C_{r + 1}}$
Solution
$^n{C_r} + 2{^n}{C_{r – 1}} + {\,^n}{C_{r – 2}} = {\,^n}{C_r} + {\,^n}{C_{r – 1}} + {\,^n}{C_{r – 1}} + {\,^n}{C_{r – 2}}$
$ = {\,^{n + 1}}{C_r} + {\,^{n + 1}}{C_{r – 1}} = {\,^{n + 2}}{C_r}$.
Standard 11
Mathematics