Left| {,begin{array}{*{20}{c}}x&4&{y + z}y&4&{z + x}z&4&{x + y}end{array},}

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3 and 4 .Determinants and Matrices

easy

$\left| {\,\begin{array}{*{20}{c}}x&4&{y + z}\\y&4&{z + x}\\z&4&{x + y}\end{array}\,} \right| = $

A

$4$

B

$x + y + z$

C

$xyz$

D

$0$

Solution

(d) Apply ${C_1} \to {C_1} + {C_3}$ and take $x + y + z$ common from ${C_1}$ and $4 $ from ${C_2}$ to make first two columns identical.

Standard 12

Mathematics

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