frac{1}{{sin 10^circ }} - frac{{sqrt 3 }}{{co | vedclass

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Question

(d) $\frac{1}{{\sin 10^\circ }} - \frac{{\sqrt 3 }}{{\cos 10^\circ }}$

$ = \frac{{2\left( {\frac{{\cos 10^\circ }}{2} - \frac{{\sqrt 3 }}{2}\sin 10

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(d) $\frac{1}{{\sin 10^\circ }} - \frac{{\sqrt 3 }}{{\cos 10^\circ }}$

$ = \frac{{2\left( {\frac{{\cos 10^\circ }}{2} - \frac{{\sqrt 3 }}{2}\sin 10^\circ } ight)}}{{(2\sin 10^\circ \cos 10^\circ ) 	imes \frac{1}{2}}}$

$ = \frac{{4\,\sin \,({{30}^o} - {{10}^o})}}{{\sin \,{{20}^o}}} $

$= \frac{{4\,\sin \,{{20}^o}}}{{\sin \,{{20}^o}}} = 4$.

$\frac{1}{{\sin 10^\circ }} - \frac{{\sqrt 3 }}{{\cos 10^\circ }} =$

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