$\cos \frac{{2\pi }}{{15}}\cos \frac{{4\pi }}{{15}}\cos \frac{{8\pi }}{{15}}\cos \frac{{16\pi }}{{15}}  =$

  • [IIT 1985]
  • A

    $1/2$

  • B

    $1/4$

  • C

    $1/8$

  • D

    $1/16$

Similar Questions

Prove that $\tan 4 x=\frac{4 \tan x\left(1-\tan ^{2} x\right)}{1-6 \tan ^{2} x+\tan ^{4} x}$

If $\sin A + \cos A = \sqrt 2 ,$ then ${\cos ^2}A = $

$\tan \alpha + 2\tan 2\alpha + 4\tan 4\alpha + 8\cot \,8\alpha = $

  • [IIT 1988]

$\tan 3A - \tan 2A - \tan A = $

If $\tan \,(A + B) = p,\,\,\tan \,(A - B) = q,$ then the value of $\tan \,2A$ in terms of $p$ and $q$ is