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3.Trigonometrical Ratios, Functions and Identities
easy
$\sin 4\theta $ ને . . . . સ્વરૂપે પણ લખી શકાય.
A
$4\sin \theta (1 - 2{\sin ^2}\theta )\sqrt {1 - {{\sin }^2}\theta } $
B
$2\sin \theta \cos \theta {\sin ^2}\theta $
C
$4\sin \theta - 6{\sin ^3}\theta $
D
એકપણ નહિ.
Solution
(a) $\sin 4\theta = 2\sin 2\theta \cos 2\theta $
$ = 2.2\sin \theta \cos \theta (1 – 2{\sin ^2}\theta )$
$ = 4\sin \theta (1 – 2{\sin ^2}\theta )\sqrt {1 – {{\sin }^2}\theta } $
Standard 11
Mathematics
