1 - 2{sin ^2}left( {frac{π }{4} + θ } right) =

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3.Trigonometrical Ratios, Functions and Identities

easy

$1 - 2{\sin ^2}\left( {\frac{\pi }{4} + \theta } \right) = $

A

$\cos 2\theta $

B

$ - \cos 2\theta $

C

$\sin 2\theta $

D

$ - \sin 2\theta $

Solution

(d) $1 – 2{\sin ^2}\left( {\frac{\pi }{4} + \theta } \right) $

$= \cos \left( {\frac{\pi }{2} + 2\theta } \right) $

$= – \sin 2\theta $.

Standard 11

Mathematics

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