$1 - 2{\sin ^2}\left( {\frac{\pi }{4} + \theta } \right) = $
$1 - 2{\sin ^2}\left( {\frac{\pi }{4} + \theta } \right) = $
- A
$\cos 2\theta $
- B
$ - \cos 2\theta $
- C
$\sin 2\theta $
- D
$ - \sin 2\theta $
Similar Questions
$\cos \alpha .\sin (\beta - \gamma ) + \cos \beta .\sin (\gamma - \alpha ) + \cos \gamma .\sin (\alpha - \beta ) = $
$\cos \alpha .\sin (\beta - \gamma ) + \cos \beta .\sin (\gamma - \alpha ) + \cos \gamma .\sin (\alpha - \beta ) = $
$\tan 5x\tan 3x\tan 2x = $
$\tan 5x\tan 3x\tan 2x = $
$\cos ^{3}\left(\frac{\pi}{8}\right) \cdot \cos \left(\frac{3 \pi}{8}\right)+\sin ^{3}\left(\frac{\pi}{8}\right) \cdot \sin \left(\frac{3 \pi}{8}\right) \text { का मान }$ है
$\cos ^{3}\left(\frac{\pi}{8}\right) \cdot \cos \left(\frac{3 \pi}{8}\right)+\sin ^{3}\left(\frac{\pi}{8}\right) \cdot \sin \left(\frac{3 \pi}{8}\right) \text { का मान }$ है
- [JEE MAIN 2020]
यदि $\sin x + \cos x = \frac{1}{5},$ तब $\tan 2x$ का मान होगा
यदि $\sin x + \cos x = \frac{1}{5},$ तब $\tan 2x$ का मान होगा
यदि $A = 133^\circ ,$ तब $\;2\cos \frac{A}{2} =$
यदि $A = 133^\circ ,$ तब $\;2\cos \frac{A}{2} =$