If tan A = frac{1}{2}, then tan 3A = | vedclass

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Question

(b) We have $	an A = \frac{1}{2}$

$ \Rightarrow 	an 3A = \frac{{3	an A - {{	an }^3}A}}{{1 - {{3+an }^2}A}} $

$= \frac{{3.\frac{1}{2} - \frac

Vedclass · Accepted Answer

$\frac{{11}}{2}$

Vedclass · Answer

(b) We have $	an A = \frac{1}{2}$

$ \Rightarrow 	an 3A = \frac{{3	an A - {{	an }^3}A}}{{1 - {{3+an }^2}A}} $

$= \frac{{3.\frac{1}{2} - \frac{1}{8}}}{{1 - 3.\frac{1}{4}}} $

$= \frac{{12 - 1}}{2} = \frac{{11}}{2}$.

If $\tan A = \frac{1}{2},$ then $\tan 3A = $

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