$\sqrt {\frac{{1 - \sin A}}{{1 + \sin A}}} = $
$\sqrt {\frac{{1 - \sin A}}{{1 + \sin A}}} = $
- A
$\sec A + \tan A$
- B
$\tan \left( {\frac{\pi }{4} - A} \right)$
- C
$\tan \left( {\frac{\pi }{4} + \frac{A}{2}} \right)$
- D
$\tan \left( {\frac{\pi }{4} - \frac{A}{2}} \right)$
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