$C$ the centre of the hyperbola $\frac{{{x^2}}}{{{a^2}}} - \frac{{{y^2}}}{{{b^2}}} = 1$. The tangents at any point $P$ on this hyperbola meets the straight lines $bx - ay = 0$ and $bx + ay = 0$ in the points $Q$ and $R$ respectively. Then $CQ\;.\;CR = $
${a^2} + {b^2}$
${a^2} - {b^2}$
$\frac{1}{{{a^2}}} + \frac{1}{{{b^2}}}$
$\frac{1}{{{a^2}}} - \frac{1}{{{b^2}}}$
An ellipse intersects the hyperbola $2 x^2-2 y^2=1$ orthogonally. The eccentricity of the ellipse is reciprocal of that of the hyperbola. If the axes of the ellipse are along the coordinate axes, then
$(A)$ Equation of ellipse is $x^2+2 y^2=2$
$(B)$ The foci of ellipse are $( \pm 1,0)$
$(C)$ Equation of ellipse is $x^2+2 y^2=4$
$(D)$ The foci of ellipse are $( \pm \sqrt{2}, 0)$
Let the hyperbola $H : \frac{ x ^{2}}{ a ^{2}}-\frac{ y ^{2}}{ b ^{2}}=1$ pass through the point $(2 \sqrt{2},-2 \sqrt{2})$. A parabola is drawn whose focus is same as the focus of $H$ with positive abscissa and the directrix of the parabola passes through the other focus of $H$. If the length of the latus rectum of the parabola is e times the length of the latus rectum of $H$, where $e$ is the eccentricity of $H$, then which of the following points lies on the parabola?
Equation of the normal to the hyperbola $\frac{{{x^2}}}{{25}} - \frac{{{y^2}}}{{16}} = 1$ perpendicular to the line $2x + y = 1$ is
The eccentricity of the hyperbola $4{x^2} - 9{y^2} = 16$, is
The equation of the hyperbola whose directrix is $x + 2y = 1$, focus $(2, 1)$ and eccentricity $2$ will be