The equation of the hyperbola whose foci are $(6, 4)$ and $(-4, 4)$ and eccentricity $2$ is given by
The equation of the hyperbola whose foci are $(6, 4)$ and $(-4, 4)$ and eccentricity $2$ is given by
- A
$12{x^2} - 4{y^2} - 24x + 32y - 127 = 0$
- B
$12{x^2} + 4{y^2} + 24x - 32y - 127 = 0$
- C
$12{x^2} - 4{y^2} - 24x - 32y + 127 = 0$
- D
$12{x^2} - 4{y^2} + 24x + 32y + 127 = 0$
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