The negation of the statement $q \wedge \left( { \sim p \vee  \sim r} \right)$

$\sim (p \vee q) \vee (\sim p \wedge q)$ is logically equivalent to

The compound statement $(\mathrm{P} \vee \mathrm{Q}) \wedge(\sim \mathrm{P}) \Rightarrow \mathrm{Q}$ is equivalent to:

$\left( {p \wedge  \sim q \wedge  \sim r} \right) \vee \left( { \sim p \wedge q \wedge  \sim r} \right) \vee \left( { \sim p \wedge  \sim q \wedge r} \right)$ is equivalent to-

The converse of the statement "If $p < q$, then $p -x < q -x"$ is –