$(\sim (\sim p)) \wedge q$ is equal to .........

The statement $(p \Rightarrow q) \vee(p \Rightarrow r)$ is NOT equivalent to.

The proposition $\left( { \sim p} \right) \vee \left( {p\, \wedge  \sim q} \right)$

The negation of the Boolean expression $((\sim q) \wedge p) \Rightarrow((\sim p) \vee q)$ is logically equivalent to

The conditional $(p \wedge q)  \Rightarrow  p$ is :-

The proposition $ \sim \left( {p\,\vee \sim q} \right) \vee  \sim \left( {p\, \vee q} \right)$ is logically equivalent to