The compound statement (mathrm{P} vee mathrm{ | vedclass

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Question

Using Truth Table

$\mathrm{P}$
			$\mathrm{Q}$
			$\mathrm{P} \vee \mathrm{Q}$
			$\sim \mathrm{P}$
			$(\mathrm{P} \vee \mathrm{Q}) \wedge

Vedclass · Accepted Answer

$\sim(P \Rightarrow Q) \Leftrightarrow P \wedge \sim Q$

Vedclass · Answer

Using Truth Table

$\mathrm{P}$
			$\mathrm{Q}$
			$\mathrm{P} \vee \mathrm{Q}$
			$\sim \mathrm{P}$
			$(\mathrm{P} \vee \mathrm{Q}) \wedge \mathrm{P}$
			$(\mathrm{P} \vee \mathrm{Q}) \wedge \sim \mathrm{P} \rightarrow \mathrm{Q}$

$T$
			$T$
			$T$
			$F$
			$F$
			$T$

$T$
			$F$
			$T$
			$F$
			$F$
			$T$

$F$
			$T$
			$T$
			$F$
			$T$
			$T$

$F$
			$F$
			$F$
			$T$
			$F$
			$T$

Check from options

The compound statement $(\mathrm{P} \vee \mathrm{Q}) \wedge(\sim \mathrm{P}) \Rightarrow \mathrm{Q}$ is equivalent to:

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