$\sim (p \vee q) \vee (\sim p \wedge q)$ is logically equivalent to
$\sim (p \vee q) \vee (\sim p \wedge q)$ is logically equivalent to
- A
$\sim p$
- B
$p$
- C
$q$
- D
$\sim q$
Similar Questions
The statement $\sim(p\leftrightarrow \sim q)$ is :
The statement $\sim(p\leftrightarrow \sim q)$ is :
- [JEE MAIN 2014]
If $p, q, r$ are simple propositions, then $(p \wedge q) \wedge (q \wedge r)$ is true then
If $p, q, r$ are simple propositions, then $(p \wedge q) \wedge (q \wedge r)$ is true then
Which of the following is not a statement
Which of the following is not a statement
Consider
Statement $-1 :$$\left( {p \wedge \sim q} \right) \wedge \left( { \sim p \wedge q} \right)$ is a fallacy.
Statement $-2 :$$(p \rightarrow q) \leftrightarrow ( \sim q \rightarrow \sim p )$ is a tautology.
Consider
Statement $-1 :$$\left( {p \wedge \sim q} \right) \wedge \left( { \sim p \wedge q} \right)$ is a fallacy.
Statement $-2 :$$(p \rightarrow q) \leftrightarrow ( \sim q \rightarrow \sim p )$ is a tautology.
- [AIEEE 2009]
The negation of the statement $q \wedge \left( { \sim p \vee \sim r} \right)$
The negation of the statement $q \wedge \left( { \sim p \vee \sim r} \right)$