$\left( {p \wedge \sim q \wedge \sim r} \right) \vee \left( { \sim p \wedge q \wedge \sim r} \right) \vee \left( { \sim p \wedge \sim q \wedge r} \right)$ is equivalent to-
$ \sim \left( {\left( {p \wedge q} \right) \vee \left( {q \wedge r} \right) \vee \left( {r \wedge p} \right)} \right)$
$p \vee q \vee r$
$ \left( {\left( {p \wedge q} \right) \vee \left( {q \wedge r} \right) \vee \left( {r \wedge p} \right)\left( {p \vee q \vee r} \right)} \right)$
$\left( { \sim \left( {(p \wedge q} \right) \vee \left( {q \wedge r} \right) \vee \left( {r \wedge p)} \right) \wedge \left( {p \vee q \vee r} \right)} \right)$
Consider the following three statements :
$(A)$ If $3+3=7$ then $4+3=8$.
$(B)$ If $5+3=8$ then earth is flat.
$(C)$ If both $(A)$ and $(B)$ are true then $5+6=17$. Then, which of the following statements is correct?
$\sim p \wedge q$ is logically equivalent to
Which of the following is not a statement
Contrapositive of the statement “If two numbers are not equal, then their squares are not equals” is
Consider the following two propositions:
$P_1: \sim( p \rightarrow \sim q )$
$P_2:( p \wedge \sim q ) \wedge((\sim p ) \vee q )$
If the proposition $p \rightarrow((\sim p ) \vee q )$ is evaluated as $FALSE$, then