$\left( {p \wedge  \sim q \wedge  \sim r} \right) \vee \left( { \sim p \wedge q \wedge  \sim r} \right) \vee \left( { \sim p \wedge  \sim q \wedge r} \right)$ is equivalent to-

  • A

    $ \sim \left( {\left( {p \wedge q} \right) \vee \left( {q \wedge r} \right) \vee \left( {r \wedge p} \right)} \right)$

  • B

    $p \vee q \vee r$

  • C

    $  \left( {\left( {p \wedge q} \right) \vee \left( {q \wedge r} \right) \vee \left( {r \wedge p} \right)\left( {p \vee q \vee r} \right)} \right)$

  • D

    $\left( { \sim \left( {(p \wedge q} \right) \vee \left( {q \wedge r} \right) \vee \left( {r \wedge p)} \right) \wedge \left( {p \vee q \vee r} \right)} \right)$

Similar Questions

Consider the following three statements :

$(A)$ If $3+3=7$ then $4+3=8$.

$(B)$ If $5+3=8$ then earth is flat.

$(C)$ If both $(A)$ and $(B)$ are true then $5+6=17$. Then, which of the following statements is correct?

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$\sim p \wedge q$ is logically equivalent to

Which of the following is not a statement

Contrapositive of the statement “If two numbers are not equal, then their squares are not equals” is

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Consider the following two propositions:

$P_1: \sim( p \rightarrow \sim q )$

$P_2:( p \wedge \sim q ) \wedge((\sim p ) \vee q )$

If the proposition $p \rightarrow((\sim p ) \vee q )$ is evaluated as $FALSE$, then

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