$\sim (p \vee (\sim q))$ is equal to .......
$\sim p \vee q$
$(\sim p) \wedge q$
$\sim p\; \vee \sim p$
$\sim p\; \wedge \sim q$
Contrapositive of the statement 'If two numbers are not equal, then their squares are not equal', is
Negation of $(p \Rightarrow q) \Rightarrow(q \Rightarrow p)$ is
If the Boolean expression $\left( {p \oplus q} \right) \wedge \left( { \sim p\,\Theta\, q} \right)$ is equivalent to $p \wedge q$, where $ \oplus $ , $\Theta \in \left\{ { \wedge , \vee } \right\}$ , ,then the ordered pair $\left( { \oplus ,\Theta } \right)$ is
Dual of $(x \vee y) \wedge (x \vee 1) = x \vee (x \wedge y) \vee y$ is
The statement $\sim(p\leftrightarrow \sim q)$ is :