The statement p rightarrow (q rightarro | vedclass

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Question

As $\mathrm{q} \rightarrow \mathrm{p}=\sim \mathrm{q} \vee \mathrm{p}$ and $\mathrm{p} \rightarrow(\mathrm{q} \rightarrow \mathrm{p})=\sim \mathrm{p}

Vedclass · Accepted Answer

$p \rightarrow  (q\, \vee \, p)$

Vedclass · Answer

As $\mathrm{q} \rightarrow \mathrm{p}=\sim \mathrm{q} \vee \mathrm{p}$ and $\mathrm{p} \rightarrow(\mathrm{q} \rightarrow \mathrm{p})=\sim \mathrm{p} \mathrm{v} \sim \mathrm{q} \vee \mathrm{p}$

The truth value of $p \rightarrow(q \rightarrow p)$ is a tautology

and truth value of $\sim \mathrm{pv} \sim \mathrm{q}$ v $\mathrm{p}$ is also a tautology

Hence $p \rightarrow(q \rightarrow p)=\sim p \vee \sim q \vee p$

The statement $p \rightarrow (q \rightarrow p)$ is equivalent to

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