The statement p to ( q to p) is equivalent to | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$q$
			$p$
			${q 	o p}$
			$p 	o \left( {q 	o p} ight)$
			${p \vee q}$
			$p 	o \left( {p \vee q} ight)$
		
		
			$T$

Vedclass · Accepted Answer

$p\, 	o \,(p \vee q)$

Vedclass · Answer

$q$
			$p$
			${q 	o p}$
			$p 	o \left( {q 	o p} ight)$
			${p \vee q}$
			$p 	o \left( {p \vee q} ight)$
		
		
			$T$
			$T$
			$T$
			$T$
			$T$
			$T$
		
		
			$T$
			$F$
			$F$
			$T$
			$T$
			$T$
		
		
			$F$
			$T$
			$T$
			$T$
			$T$
			$T$
		
		
			$F$
			$F$
			$T$
			$T$
			$F$
			$T$
		
	


Since truth value of  $p 	o \left( {q 	o p} ight)$ and $p 	o \left( {p \vee q} ight)$ are same, hence $p 	o \left( {q 	o p} ight)$ is equivalent to $p 	o \left( {p \vee q} ight)$.

The statement $p \to ( q \to p)$ is equivalent to

Similar Questions

Among the two statements

$(S1):$ $( p \Rightarrow q ) \wedge( q \wedge(\sim q ))$ is a contradiction and

$( S 2):( p \wedge q ) \vee((\sim p ) \wedge q ) \vee$

$( p \wedge(\sim q )) \vee((\sim p ) \wedge(\sim q ))$ is a tautology

Statement$-I :$ $\sim (p\leftrightarrow q)$ is equivalent to $(p\wedge \sim q)\vee \sim (p\vee \sim q) .$
Statement$-II :$ $p\rightarrow (p\rightarrow q)$ is a tautology.

Which statement given below is tautology ?

The inverse of the proposition $(p\; \wedge \sim q) \Rightarrow r$ is

$\sim (p \wedge q)$ is equal to .....