Pascal-Second has dimension of | vedclass

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Question

Pascal is unit of pressure, hence its dimensional formula is
$\left[M L^{-1} T^{-2}ight]$
$	herefore$ Dimensional formula of Pascal-second is $\l

Vedclass · Accepted Answer

Coefficient of viscosity

Vedclass · Answer

Pascal is unit of pressure, hence its dimensional formula is
$\left[M L^{-1} T^{-2}ight]$
$	herefore$ Dimensional formula of Pascal-second is $\left[M L^{-1} T^{-1}ight]$
By the formula of coefficient of viscosity, we have
$\eta=\frac{F}{A(\Delta v / \Delta z)}$
where $F$ is force, $A$ is area and $\frac{\Delta v}{\Delta z}$ is velocity gradient.
$	herefore$ Dimensions of $\eta=\frac{\left[M L T^{-2}ight]}{\left[L^{2}ight]\left[L T^{-1} / Light]}$
$=\left[M L^{-1} T^{-1}ight]$
Hence, Pascal-second has dimensions of coefficient of viscosity.

$Pascal-Second$ has dimension of

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