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1.Units, Dimensions and Measurement
hard
The dimensional formula of angular impulse is:
A$\left[\mathrm{M} \mathrm{L}^2 \mathrm{~T}^1\right]$
B$\left[\mathrm{M} \mathrm{L}^2 \mathrm{~T}^2\right]$
C$\left[\mathrm{ML} \mathrm{T}{ }^{-1}\right]$
D$\left[\mathrm{M} \mathrm{L}^2 \mathrm{~T}^{-1}\right]$
(JEE MAIN-2024)
Solution
Angular impulse $=$ change in angular momentum.
[Angular impulse $]=[$ Angular momentum $]=[\mathrm{mvr}]$
$=\left[\mathrm{ML}^2 \mathrm{~T}^{-1}\right]$
[Angular impulse $]=[$ Angular momentum $]=[\mathrm{mvr}]$
$=\left[\mathrm{ML}^2 \mathrm{~T}^{-1}\right]$
Standard 11
Physics
Similar Questions
Match List $I$ with List $II$
| LIST$-I$ | LIST$-II$ |
| $(A)$ Torque | $(I)$ $ML ^{-2} T ^{-2}$ |
| $(B)$ Stress | $(II)$ $ML ^2 T ^{-2}$ |
| $(C)$ Pressure of gradient | $(III)$ $ML ^{-1} T ^{-1}$ |
| $(D)$ Coefficient of viscosity | $(IV)$ $ML ^{-1} T ^{-2}$ |
