64 small drops of mercury, each of radius r | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(d) $\frac{{{\sigma _{small}}}}{{{\sigma _{Big}}}} = \frac{q}{Q} 	imes \frac{{{R^2}}}{{{r^2}}} = \frac{q}{{(nq)}} 	imes \frac{{{{({n^{1/3}}r)}^2}}}{

Vedclass · Accepted Answer

$1:4$

Vedclass · Answer

(d) $\frac{{{\sigma _{small}}}}{{{\sigma _{Big}}}} = \frac{q}{Q} 	imes \frac{{{R^2}}}{{{r^2}}} = \frac{q}{{(nq)}} 	imes \frac{{{{({n^{1/3}}r)}^2}}}{{{r^2}}}$$ = {n^{ - 1/3}} = {(64)^{ - 1/3}} = \frac{1}{4}$

$64$ small drops of mercury, each of radius $ r$ and charge $q$ coalesce to form a big drop. The ratio of the surface density of charge of each small drop with that of the big drop is

Similar Questions

Two metal spheres, one of radius $R$ and the other of radius $2R$, both have same surface charge density $\sigma $. They are brought in contact and separated. What will be new surface charge densities on them ?

A conducting sphere $A$ of radius $a$, with charge $Q$, is placed concentrically inside a conducting shell $B$ of radius $b$. $B$ is earthed. $C$ is the common centre of the $A$ and $B$.

Figure shows three concentric metallic spherical shells. The outermost shell has charge $q_2$, the inner most shell has charge $q_1$, and the middle shell is uncharged. The charge appearing on the inner surface of outermost shell is

Can a metal be used as a medium for dielectric

A hollow conducting sphere of inner radius $R$ and outer radius $2R$ is given a charge $Q$ as shown in the figure, then the :