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6-2.Equilibrium-II (Ionic Equilibrium)
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$10\, M\, CH_3COOH$ દ્રાવણ માટે $K_a$ = $10^{-5}$ તો , $[H^+]$ અને $pH$ નું મુલ્ય અનુક્રમે શું હશે ?

A

$10^{-3}$,$10^{-3}$,$5$

B

$10^{-3}$, $10^{-2}$,$2$

C

$10^{-5}$, $10^{-3}$,$4$

D

$10^{-6}$, $10^{-3}$,$7$

Solution

${K_a} = C{\alpha ^2}\,\,\,\, \Rightarrow \,\,\,{10^{ – 5}} = 10{\alpha ^2}\,\,\,\, \Rightarrow \,\,\,{\alpha ^2} = \frac{{{{10}^{ – 5}}}}{{10}}\,\,\,\, \Rightarrow \,\,\,{\alpha ^2} = {10^{ – 6}}\,\,\,\,\, \Rightarrow \,\,\,\,\alpha  = {10^{ – 3}}$

$[{H^ + }] = C\alpha  = 10 \times {10^{ – 3}} = {10^{ – 2}}$

$pH =  – \log [{H^ + }] =  – \log [{10^{ – 2}}] = 2$

Standard 11
Chemistry

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