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6-2.Equilibrium-II (Ionic Equilibrium)
medium
$10\, M\, CH_3COOH$ દ્રાવણ માટે $K_a$ = $10^{-5}$ તો , $[H^+]$ અને $pH$ નું મુલ્ય અનુક્રમે શું હશે ?
A
$10^{-3}$,$10^{-3}$,$5$
B
$10^{-3}$, $10^{-2}$,$2$
C
$10^{-5}$, $10^{-3}$,$4$
D
$10^{-6}$, $10^{-3}$,$7$
Solution
${K_a} = C{\alpha ^2}\,\,\,\, \Rightarrow \,\,\,{10^{ – 5}} = 10{\alpha ^2}\,\,\,\, \Rightarrow \,\,\,{\alpha ^2} = \frac{{{{10}^{ – 5}}}}{{10}}\,\,\,\, \Rightarrow \,\,\,{\alpha ^2} = {10^{ – 6}}\,\,\,\,\, \Rightarrow \,\,\,\,\alpha = {10^{ – 3}}$
$[{H^ + }] = C\alpha = 10 \times {10^{ – 3}} = {10^{ – 2}}$
$pH = – \log [{H^ + }] = – \log [{10^{ – 2}}] = 2$
Standard 11
Chemistry