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6-2.Equilibrium-II (Ionic Equilibrium)
hard
વિયોજન અચળાંક $K_a$ ના મૂલ્યો નીચે આપેલા છે
| ઍસિડ | $K_a$ |
| $HCN$ | $6.2\times 10^{-10}$ |
| $HF$ | $7.2\times 10^{-4}$ |
| $HNO_2$ | $4.0\times 10^{-4}$ |
તો બેઇઝ $CN^-,F^-$ અને $NO_2^-$ ની બેઝિક પ્રબળાતાનો સાચો વધતો ક્રમ જણાવો.
A
$F^- < CN^- < NO_2^-$
B
$NO_2^- < CN^- < F^-$
C
$F^- < NO_2^- < CN^-$
D
$NO_2^- < F^- < CN^-$
(JEE MAIN-2013)
Solution
Higher the value of $K_a$ lower will be the value of $pK_a$ $i.e.$ higher will be the acidic nature. Further since $CN^-, F^-$ and $NO_2^-$ are conjugate base of the acids $HCN, HF$ and $HNO_2$ respectively hence the correct order of base strength will be $F^- < NO_2^- < CN^-$ ( $\because $ stronger the acid weaker will be its conjugate base)
Standard 11
Chemistry
